ARM Assembly Language Programming & Architecture (ARM books Book 1) by Muhammad Ali Mazidi & Sarmad Naimi & Sepehr Naimi & Janice Mazidi

Author:Muhammad Ali Mazidi & Sarmad Naimi & Sepehr Naimi & Janice Mazidi [Mazidi, Muhammad Ali]
Language: eng
Format: azw3, pdf
Publisher: Mazidi & Naimi
Published: 2014-01-20T05:00:00+00:00

For an ARM system of 100 MHz, find how long it takes to execute each of the following instructions:

(a) MOV (b) SUB (c) B

(d) ADD (e) NOP (f) BHI

(g) BLO (h) BNE (i) EQU

Solution:

The machine cycle for a system of 100 MHz is 10 ns, as shown in Example 4-9. Therefore, we have:

Instruction Instruction cycles Time to execute

(a) MOV 1 1 × 10 ns = 10 ns

(b) SUB 1 1 × 10 ns = 10 ns

(c) B 3 3 × 10 ns = 30 ns

(d) ADD 1 1 × 10 ns = 10 ns

(e) NOP 1 1 × 10 ns = 10 ns

For the following, due to branch penalty, 3 clock cycles if taken and 1 if it falls through:

(f) BHI 3/1 3 × 10 ns = 30 ns

(g) BLO 3/1 3 × 10 ns = 30 ns

(h) BNE 3/1 3 × 10 ns = 30 ns

(i) EQU 0 (directives do not produce machine instructions)

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